llvm.org GIT mirror llvm / 8b2e141 runtime / GCCLibraries / libc / atox.c
8b2e141

Tree @8b2e141 (Download .tar.gz)

atox.c @8b2e141raw · history · blame

//===-- atox.c - Ascii string parsers for LLVM libc Library -------*- C -*-===//
// 
// A lot of this code is ripped gratuitously from glibc and libiberty.
//
//===----------------------------------------------------------------------===//


#define isspace(x) ((x) == ' ' || (x) == '\t' || (x) == '\n')
#define isdigit(x) ((x) >= '0' && (x) <= '9')
#define isupper(x) ((x) >= 'A' && (x) <= 'Z')
#define islower(x) ((x) >= 'a' && (x) <= 'z')
#define isalpha(x) (isupper(x) || islower(x))

#ifndef ULONG_MAX
#define ULONG_MAX       ((unsigned long)(~0L))          /* 0xFFFFFFFF */
#endif

#ifndef LONG_MAX
#define LONG_MAX        ((long)(ULONG_MAX >> 1))        /* 0x7FFFFFFF */
#endif

#ifndef LONG_MIN
#define LONG_MIN        ((long)(~LONG_MAX))             /* 0x80000000 */
#endif

#if 0
/*
 * Convert a string to a long integer.
 *
 * Ignores `locale' stuff.  Assumes that the upper and lower case
 * alphabets and digits are each contiguous.
 */
long strtol(const char *nptr, char **endptr, int base) {
        register const char *s = nptr;
        register unsigned long acc;
        register int c;
        register unsigned long cutoff;
        register int neg = 0, any, cutlim;

        /*
         * Skip white space and pick up leading +/- sign if any.
         * If base is 0, allow 0x for hex and 0 for octal, else
         * assume decimal; if base is already 16, allow 0x.
         */
        do {
                c = *s++;
        } while (isspace(c));
        if (c == '-') {
                neg = 1;
                c = *s++;
        } else if (c == '+')
                c = *s++;
        if ((base == 0 || base == 16) &&
            c == '0' && (*s == 'x' || *s == 'X')) {
                c = s[1];
                s += 2;
                base = 16;
        }
        if (base == 0)
                base = c == '0' ? 8 : 10;

        /*
         * Compute the cutoff value between legal numbers and illegal
         * numbers.  That is the largest legal value, divided by the
         * base.  An input number that is greater than this value, if
         * followed by a legal input character, is too big.  One that
         * is equal to this value may be valid or not; the limit
         * between valid and invalid numbers is then based on the last
         * digit.  For instance, if the range for longs is
         * [-2147483648..2147483647] and the input base is 10,
         * cutoff will be set to 214748364 and cutlim to either
         * 7 (neg==0) or 8 (neg==1), meaning that if we have accumulated
         * a value > 214748364, or equal but the next digit is > 7 (or 8),
         * the number is too big, and we will return a range error.
         *
         * Set any if any `digits' consumed; make it negative to indicate
         * overflow.
         */
        cutoff = neg ? -(unsigned long)LONG_MIN : LONG_MAX;
        cutlim = cutoff % (unsigned long)base;
        cutoff /= (unsigned long)base;
        for (acc = 0, any = 0;; c = *s++) {
                if (isdigit(c))
                        c -= '0';
                else if (isalpha(c))
                        c -= isupper(c) ? 'A' - 10 : 'a' - 10;
                else
                        break;
                if (c >= base)
                        break;
                if (any < 0 || acc > cutoff || acc == cutoff && c > cutlim)
                        any = -1;
                else {
                        any = 1;
                        acc *= base;
                        acc += c;
                }
        }
        if (any < 0) {
                acc = neg ? LONG_MIN : LONG_MAX;
        } else if (neg)
                acc = -acc;
        if (endptr != 0)
                *endptr = (char *) (any ? s - 1 : nptr);
        return (acc);
}


/* Convert a string to an int.  */
int atoi(const char *nptr) {
  return (int)strtol(nptr, 0, 10);
}

/* Convert a string to a long int.  */
long int atol(const char *nptr) {
  return strtol(nptr, 0, 10);
}
#endif